Question

2y-1/4y+1 =1/5
.
please solve this​

Answer 1

Answer:

$\frac{2y - 1}{4y + 1} = \frac{1}{5}$

$5(2y - 1) = 4y + 1$

$10y - 5 = 4y + 1$

$10y - 4y = 1 + 5$

$6y = 6$

$y = \frac{6}{6}$

$y = 1$

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Answer 2

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\sf \bf \dfrac{2y-1}{4y+1}=\dfrac{1}{5}$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf \implies \dfrac{2y-1}{4y+1}=\dfrac{1}{5}$

$\sf \bf \implies 5 \Big(2y-1\Big)=1 \Big(4y+1\Big)$

$\sf \bf \implies 10y-5=4y+1$

$\sf \bf \implies 10y-4y=1+5$

$\sf \bf \implies 6y=6$

$\sf \bf \implies y=\cancel{\dfrac{6}{6}}$

$\implies {\boxed {\boxed {\color {blue} {\sf \bf y=1}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

__________________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

${\color {green} {\tt Identities}}$

$\sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}$

$\sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$\sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}$