Question

(2y+1) (y-3)-3y (y+2)=y(2-y)+10. find the value of x.urgent

Answer 1

questions me x kaha h mere bhai..

Answer 2

Answer:

There is no x in the equation

y=-1

Step-by-step explanation:

(2y+1)(y-3)-3y(y+2)=y(2-y)+10

2y(y-3)+1(y-3)-3y^2-6y=2y-y^2+10

2y^2-6y+y-3-3y^2-6y=2y-y^2+10

2y^2-3y^2-6y-6y+y-3=2y-y^2+10

-y^2-12y+y=2y-y^2+10+3

-y^2+y^2-12y-2y+y=13

-14y+y=13

-13y=13

y=13/-13

y=-1