Question

2y^2+27y+13=0 quadratik equation by factorisation​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

2y^2+27y+13=0

2y^2+26y+y+13=0

(2y^2+y)+(26y+13)=0

y(2y+1)+13(2y+1)=0

(2y+1)(y+13)= 0

2y+1=0. |. y+13=0

2y=-1. |. y=-13

y=-1/2. |