Question

2y^2/5 -y-3/5=0 find roots by factorization​

Answer 1

Step-by-step explanation:

$2 {y}^{ \frac{2}{5}} - {y}^{ - \frac{3}{5} } = 0 = >$

Multiply on both sides by y^3/5 then we get

$2 {y}^{ \frac{2 + 3}{5} } - {y}^{ \frac{3 - 3}{5}} = 0 = > 2y - 1 = 0 = >$

$y = \frac{1}{2}$

Hope it helps you.