Math, asked by somendra8825, 11 months ago

(2y-3)/4 - (y-2)/2=(6y+5)/4

Answers

Answered by tanmays2006
1

Answer:

y= -2/3

Step-by-step explanation:

(2y-3)/4 - (y-2)/2=(6y+5)/4

2y-3-2y+4/4 = (6y+5)/4

1 = 6y +5

6y= -4

3y= -2

y= -2/3

Answered by Delta13
3

We have,

 \frac{2y - 3}{4}  -  \frac{y - 2}{2}  =  \frac{6y + 5}{4}  \\

First we will take LCM

 =  >  \frac{2y - 3}{4}  -  \frac{y - 2}{2}  =  \frac{6y + 5}{4}  \\  \\  =  >  \frac{2y - 3 - (y - 2)(2)}{4}  =  \frac{6y + 5}{4}  \\  \\  =  >  \frac{2y - 3 - (2y - 4)}{4}  =  \frac{6y + 5}{4}  \\  \\  =  >  \frac{2y - 3 - 2y + 4}{4}  =  \frac{6y + 5}{4}  \\  \\  =  >   \frac{ \cancel{2y} - 3  \:  \:  \cancel{ - 2y} + 4}{ \cancel{4}}  =  \frac{6y + 5}{ \cancel{4}}  \\  \\  =  > 1 = 6y + 5 \\  \\  =  > 1 - 5 = 6y \\ or \\  =  > 6y = 1 - 5 \\  \\  =  > 6y =  - 4 \\  \\  =  > y =  \frac{ - 4}{ \: 6}  \\  \\  =  >  \boxed{ \red{y =  \frac{ - 2}{ \: 3} }}

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