Question

(2y+5)*(y+1)=(2y+3)*(y-1)

Answer 1

Step-by-step explanation:

$(2y + 5) \times (y + 1) = (2y + 3) \times (y - 1)$

$2 {y}^{2} + 2y + 5y + 5 = 2 {y}^{2} - 2y + 3y - 3$

$2 {y}^{2} - 2 {y}^{2} + 2y + 5y + 2y - 3y + 5 + 3 = 0$

$6y + 8 = 0$

$6y = - 8$

$y = - \frac{8}{6}$

$y = - \frac{4}{3}$