Math, asked by bharathb4908, 8 months ago

2y-x=8 , 5y-X=14, and y-2x=1​

Answers

Answered by Anonymous
1

Answer:

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Step-by-step explanation:

2y - x = 8  

x = 2y - 8

Also, 5y - x = 14

But x = 2y - 8

So, 5y - 2y = 6 ⇒ 3y = 6 ⇒ y = 2

x = 2y - 8 = 4 - 8 = -4

So, y = 2 and x = -4

Answered by Anonymous
4

2y−x=8

2y−x=8

5y−x=14

5y−x=14

y−2x=1

y−2x=1

Now,

2y−x=8

2y−x=8

x=2y−8

x=2y−8

When

y=2

y=2

then

x=−4

x=−4

When

y=5

y=5

then

x=2

x=2

Thus, we have the following table giving points on the line

2y−x=8

2y−x=8

x -4 2

y 2 5

Now,

5y−x=14

5y−x=14

x=5y−14

x=5y−14

When

y=2

y=2

, then

x=1

x=1

When

y=3

y=3

, then

x=1

x=1

Thus, we have the following table giving points on the line

5y−x=14

5y−x=14

x -4 1

y 2 3

We have,

y−2x=1

y−2x=1

x=

y−1

2

x=y−12

When

y=−1

y=−1

, then

x=1

x=1

When

y=3

y=3

, then

x=1

x=1

Thus, we have the following table giving points on the line

y−2x=1

y−2x=1

x -1 1

y -1 3

From the graph of the lines represent by the given equation, we observe that the lines taken in pairs intersect at points A(-4, 2) B(1, 3) and C(2, 5).

Hence the vertices of the triangle are A(-4, 2) B(1, 3) and C(2, 5).

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