2y²-19y+44 factorise
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Answer:
Factoring 2y2-19y+44
The first term is, 2y2 its coefficient is 2 .
The middle term is, -19y its coefficient is -19 .
The last term, "the constant", is +44
Step-1 : Multiply the coefficient of the first term by the constant 2 • 44 = 88
Step-2 : Find two factors of 88 whose sum equals the coefficient of the middle term, which is -19 .
-88 + -1 = -89
-44 + -2 = -46
-22 + -4 = -26
-11 + -8 = -19 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -11 and -8
2y2 - 11y - 8y - 44
Step-4 : Add up the first 2 terms, pulling out like factors :
y • (2y-11)
Add up the last 2 terms, pulling out common factors :
4 • (2y-11)
Step-5 : Add up the four terms of step 4 :
(y-4) • (2y-11)
Which is the desired factorization
Step-by-step explanation:
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