2y²+27y+13=0 by formula
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Answer:
2y2 + 27y + 13 = 0
2y2 + 26y + y + 13 = 0
2y(y +13) + 1(y + 13) = 0
= (2y + 1)(y +13)
either, (2y + 1) = 0
2y = -1
y = -1/2
or,
(y + 13) = 0
y = - 13
Answered by
1
Step-by-step explanation:
LHS = 2y^2+27y+13
= 2y^2+y+26y+13
= y(2y+1)+13(2y+1)
= (y+13)(2y+1)Ans
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