Math, asked by shaikhtalib37, 4 hours ago

2y²+27y+13=0 by formula​

Answers

Answered by sanaamulla53
0

Answer:

2y2 + 27y + 13 = 0

2y2 + 26y + y + 13 = 0

2y(y +13) + 1(y + 13) = 0

= (2y + 1)(y +13)

either, (2y + 1) = 0

2y = -1

y = -1/2

or,

(y + 13) = 0

y = - 13

Answered by RowdyAjay
1

Step-by-step explanation:

LHS = 2y^2+27y+13

= 2y^2+y+26y+13

= y(2y+1)+13(2y+1)

= (y+13)(2y+1)Ans

This may help you

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