Question

2y²+27y+13=0 Solve this quadratic equation by factorisation.

Answer 1

Solution:-

given by quadratic equation:-
$2 {y}^{2} + 27y + 13 = 0 \\ 2 {y}^{2} + 26y + y + 13 = 0 \\ 2y(y + 13) + 1(y + 13) = 0 \\ (y + 13)(2y + 1) = 0 \\ y + 13 = 0 \\ y = -13 \\ y = \frac{ - 1}{2}$
here y =( -13 , -1/2)

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Answer 2

SOLUTION IS IN THE ATTACHMENT.

THE SOLUTION OF QUADRATIC EQUATION BY FACTORISATION:
To find the solution of a quadratic equation by factorisation method, we first write a given quadratic polynomial as product of two linear factors by splitting the middle term and then equate each factor to zero to get desired roots of given quadratic equation.


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