x²-15x+54=0 Solve this quadratic equation by factorisation.
Answers
Answered by
52
Hi ,
It is given that ,
x² -15x + 54 = 0
Splitting the middle term ,
x² - 9x - 6x + 54 = 0
x( x - 9 ) - 6( x - 9 ) = 0
( x - 9 )( x - 6 ) = 0
x - 9 = 0 or x - 6 = 0
x = 9 or x = 6
Therefore ,
6 , 9 are roots of given quadratic
equation.
I hope this helps you.
: )
It is given that ,
x² -15x + 54 = 0
Splitting the middle term ,
x² - 9x - 6x + 54 = 0
x( x - 9 ) - 6( x - 9 ) = 0
( x - 9 )( x - 6 ) = 0
x - 9 = 0 or x - 6 = 0
x = 9 or x = 6
Therefore ,
6 , 9 are roots of given quadratic
equation.
I hope this helps you.
: )
Kalpeshbhakarr:
thanks
Answered by
7
Answer:
x² – 15x + 54 = 0
⇒x²−9x−6x+54=0
⇒x(x−9)−6(x−9)=0
⇒(x−6)(x−9)=0
⇒(x−6)=0 or (x−9)=0
⇒x=6 or x=9 .
So, 6 and 9 are the roots of the given quadratic equation.
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