Question

2y² + 3√5y + 5 Factorise and find relationship between the zeros and the coefficient​

Answer 1

Answer:

Find the zeros

y²+3/2√5y-5

Step-by-step explanation:

y²+3/2√5y-5=0

Splitting the middle term

y²+4/2√5y-√5/2y-5=0

Taking LCM

2y²+4√5y-√5y-10=0 (Denominator taken to RHS)

2y(y+2√5)-√5(y+2√5)=0

(2y-√5)(y+2√5)=0

∴y= √5/2 or -2√5

Hope you understood