Question

2y²-7y+2=0 Determine the nature of roots of this quadratic equation.

Answer 1

Hi ,

Compare 2y² -7y + 2 = 0 with

ay² + by + c = 0 we get ,

a = 2 , b = -7 , c = 2

Discreaminant ( D ) = b² - 4ac

D = ( -7 )² - 4 × 2 × 2

D = 49 - 16

D = 33

D > 0

Therefore ,

Roots of the given quadratic equation

are real and distinct.

I hope this helps you.

: )

Answer 2

Heya !!



2Y² - 7Y + 2 = 0



Here,


A = 2 , B = -7 and C = 2


Discriminant ( D ) = B²-4AC

=> (-7)² - 4 × 2 × 2



=> 49 - 16


=> 33



33 is greater than 0.


So,


The given equation have real Root's.