2y²+9y+10=0 Solve this quadratic equation by completing the square method.
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Answered by
36
Hi ,
Given quadratic equation is
2y² + 9y + 10 = 0
divide each term with 2 we get
y² + 9y/2 + 5 = 0
y² + 9y/2 = -5
y² + 2 × y × 9/4 = -5
y² + 2 ×y × 9/4 + ( 9/4 )² = ( 9/4 )² - 5
( y + 9/4 )² = 81/16 - 5
( y + 9/4 )² = ( 81 - 80 )/16
( y + 9/4 )² = 1/16
y + 9/4 = ± √1/16
y + 9/4 = ± 1/4
y = -9/4 ± 1/4
Therefore ,
y = ( - 9 ± 1 )/4
y = -8/4 or y = -10/4
y = -2 or y = -5/2
I hope this helps you.
: )
Given quadratic equation is
2y² + 9y + 10 = 0
divide each term with 2 we get
y² + 9y/2 + 5 = 0
y² + 9y/2 = -5
y² + 2 × y × 9/4 = -5
y² + 2 ×y × 9/4 + ( 9/4 )² = ( 9/4 )² - 5
( y + 9/4 )² = 81/16 - 5
( y + 9/4 )² = ( 81 - 80 )/16
( y + 9/4 )² = 1/16
y + 9/4 = ± √1/16
y + 9/4 = ± 1/4
y = -9/4 ± 1/4
Therefore ,
y = ( - 9 ± 1 )/4
y = -8/4 or y = -10/4
y = -2 or y = -5/2
I hope this helps you.
: )
Answered by
2
Answer:
2y²+9y+10=0 solve by formula method
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