2y²-9y+12=0. I hope you have solved
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Given Equation is 2y^2 - 9y + 12 = 0
it is in the form of ax^2 + bx + c = 0.
According to the Quadratic formula,y, the solution for ax^2 + bx + c , where a,b and c are numbers often called as coefficients, is given by,
(1) y = -b + root b^2 - 4ac/2a
= -(-9) + root (-9)^2 - 4 * 2 * 12/2 * 2
= 9 + root 15 i/4
= 9/4 + i root15/4.
= 2.2500 + 0.9682i
(2) y = -b - root b^2 - 4ac
= -(-9) - root (-9)^2 - 4(2)(12)/2 * 2
= 9 - root 15 i/4
= 9/4 - i root 15/4
= 2.2500 - 0.9682i
Hope this helps!
it is in the form of ax^2 + bx + c = 0.
According to the Quadratic formula,y, the solution for ax^2 + bx + c , where a,b and c are numbers often called as coefficients, is given by,
(1) y = -b + root b^2 - 4ac/2a
= -(-9) + root (-9)^2 - 4 * 2 * 12/2 * 2
= 9 + root 15 i/4
= 9/4 + i root15/4.
= 2.2500 + 0.9682i
(2) y = -b - root b^2 - 4ac
= -(-9) - root (-9)^2 - 4(2)(12)/2 * 2
= 9 - root 15 i/4
= 9/4 - i root 15/4
= 2.2500 - 0.9682i
Hope this helps!
Anonymous:
hai you leave as 9+-underout -15/4
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