Question

2y³+y²–2y–1. factorise it​

Answer 1

Answer:

y2 (2y-1) -1(2 y-1)

(2y+1) (y2 -1)

(2y+1) (y+1) (y-1)

Answer 2

Answer:

Given that 2y³+y²-2y-1

=(2y+1)(y+1)(y-1)

Now Factorizing

2y³+y²-2y-1

= y² (2y + 1) -1 (2y + 1)

= (2y + 1)(y² – 1)

= (2y + 1)(y² – 1²)

= (2y + 1) (y + 1) (y – 1)

By algebraic identity:

a² – b² = (a + b) (a – b)

Therefore,

2y³ + y² – 2y – 1 = (2y + 1) (y + 1) (y-1)

I hope this helps you.