2z² - 8 using splitting up the middle term
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which class question it permuntation and combination?
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Given equation=
2z^2 +0z -8= 0
2z^2 -4z +4z -8= 0
2z(z-2) + 4(z-2) = 0
(2z+4)(z-2) = 0
2(z+2)(z-2) =0
Therefore ,
z = -2,2
2z^2 +0z -8= 0
2z^2 -4z +4z -8= 0
2z(z-2) + 4(z-2) = 0
(2z+4)(z-2) = 0
2(z+2)(z-2) =0
Therefore ,
z = -2,2
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