Question

3.0 i velocity of the particle is v=3t +5t2
Then calculate the distance travelled
by
it between t = 1s and t= 3s​

Answer 1

Given,

v=(2t+3)m/s

The average velocity in interval 0≤t≤1,

v

avg

=

∫

0

1

dt

∫

0

1

vdt

v

avg

=

∫

0

1

dt

∫

0

1

(2t+3)dt

v

avg

=

t∣

0

1

t

2

+3t∣

0

1

=

1−0

(1

2

+3×1)−(0−0)

v

avg

=4m/s