Question

3.01 × 1022 molecules of sucrose are present in 200 ml of its solution. The concentration of the solution is

Answer 1

The concentration of the solution is 0.25M

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

${\text{Number of moles of sucrose}}=\frac{3.01\times 10^{22}}{6.023\times 10^{23}}=0.05moles$

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute = 0.05

$V_s$ = volume of solution in ml = 200 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.05moles\times 1000}{200ml}=0.25mole/L$

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