Question

3.011x10" molecules of
sucrose
are
present in 5oo ml of its
aquous solution.
Molarity of of the

solution
​

Answer 1

Answer:

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Answer 2

Explanation:

The first thing to focus on here is finding the density of the solution.

As you know, density is defined as mass per unit of volume. You know that your solution has a volume of 104 mL, which means that you only have to figure out its mass in order to be able to calculate its density.

Notice that you are given the volume of water and its density. Use this information to find the mass of water used to make the solution - keep in mind that you have 1 cm3=1 mL.

100.0mL⋅density of water1.00 g1mL=100.0 g

So, the total mass of the solution will be equal to

msol=mH3PO4+mwater

msol=10.0 g+100.0 g=110.0 g

The density of the solution will thus be

ρ=110.0 g104 mL=1.06 g mL−1

To get the mole fraction of phosphoric acid in this solution, you need to know

the number of moles of phosphoric acid

the number of moles of water

Since you have the masses of the two compounds, you can use their molar masses to determine how many moles of each you have present in this solution.

10.0g⋅1 mole H3PO497.995g=0.10205 moles H3PO4

and

100.0g⋅1 mole H2O18.015g=5.551 moles H2O

The total number of moles in this solution will be

ntotal=0.1025 moles+5.551 moles=5.6531 moles

The mole fraction of phosphoric acid will be

χH3PO4=0.10205

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