Question

(3×-1) (×-2) = (×+6) (×-1)​

Answer 1

AnswEr:

values of x are (3 + √5) and (3 - √5).

Step-by-step explanation:

(3x 1) (x - 2) = (x + 6) (x - 1)

By multiplying horizontally.

=> 3x (x - 2) - 1 (x - 2) = x (x - 1) + 6 (x - 1)

=> 3x² - 6x - x + 2 = x² - x + 6x - 6

=> 3x² - x² - 7x - 5x + 2 + 6 = 0

=> 2x² - 12x + 8 = 0

Taking 2 as common,

=> x² - 6x + 4 = 0

By using quadratic formula, we get,

=> x = 3 ± √5

Hence, values of x are (3 + √5) and (3 - √5).

Answer 2

Answer:

Given:

• [(3x 1) (x - 2)] = [(x + 6) (x - 1)]

Find:

• Find the value of x.

According to the question:

• [(3x 1) (x - 2)] = [(x + 6) (x - 1)]

Let's take the common numbers, variables out:

⇒ 3x (x - 2) - 1 (x - 2) = x (x - 1) + 6 (x - 1)

⇒ [(3x² - 6x) - (x + 2)]= [(x² - x) + (6x - 6)]

⇒ [(3x² - x²) - (7x - 5x)] + (2 + 6) = 0

⇒ (2x² - 12x) + 8 = 0

Note:

• Sometimes when there a brackets between some number and that bracket means multiplication sign.

Here, 2 is the common number.

⇒ (x² - 6x) + 4 = 0

Using quadratic formula:

⇒ x = 3 ± √5

Therefore, (3 + √5) and (3 - √5) are the values of x.