Question

(3)^1/2cosec20a-sec20a=

Answer 1

Helloo!!

√3 coses 20 - sec 20= 
√3/sin 20-1/sec20 
[√3 cos 20-sin 20]/[sin 20 cos 20] 
4[(√3/2 cos 20-1/2 sin 20)]/[2 sin 20 cos 20] 
4[cos 30*cos 20-sin 30*sin20]/[sin(20+20)+sin(20+20)] 
4[(cos(30+20))/sin40] 
4[cos 50]/sin 40 
4(cos(90-40))/sin 40 
4 sin 40/sin 40 
4 

Hope it helps