(√3+1) (√3-1) (2-√3) (4+2√3)
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Answered by
0
Answer:
(√3+1) (√3-1) (2-√3) (4+2√3)= 4
Answered by
1
Answer:
4
Step-by-step explanation:
(√3+1) (√3-1) (2-√3) (2×2 + 2×√3)
=> [(√3+1) (√3-1)] × 2[(2-√3) (2+√3)]
By using identity (a+b)(a-b) = a^2 - b^2
=> [(√3)^2 - (1)^2] × 2[(2^2) - (√3)^2]
=> (3 - 1) × 2(4 - 3)
=> 2 × 2
=> 4
Hope this will help you
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