Question

3+1/√3+1/√3+3+1/√3-3

Answer 1

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$=>3 + \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{3} + 3} + \frac{1}{ \sqrt{3} - 3} \\ \\ = > \frac{3 \sqrt{3} + 1 }{ \sqrt{3} } + \frac{ \sqrt{3} - 3 + \sqrt{3} + 3 }{ - 6} \\ \\ = > \frac{ - 18\sqrt{3} - 6 + 3 - 3 \sqrt{3} + 3 + 3 \sqrt{3} }{ - 6 \sqrt{3} } \\ \\ = > \frac{18\sqrt{3}}{6 \sqrt{3} } = > 3$
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Answer 2

$= > 3 + \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{3} + 3} + \frac{1}{ \sqrt{3} - 3 } \\ \\ = > \frac{3 \sqrt{3} + 1 }{ \sqrt{3} } + \frac{ \sqrt{3} - 3 + \sqrt{3} + 3 }{ { \sqrt{3} }^{2} - {3}^{2} } \\ \\ = > \frac{3 \sqrt{3} + 1 }{ \sqrt{3} } - \frac{2 \sqrt{3} }{6} \\ \\ = > \frac{18 \sqrt{3} + 6 - 6 }{6 \sqrt{3} } = 3$
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