Math, asked by sritiksingh790, 5 months ago

√3 1 (3- cot 30°)= tan3 60°-2 sin60°

Answers

Answered by brundag

1

Answer:

I have not learned this

Answered by aishanisinha90

0

Answer:

LHS=(

3

+1)(3−cot30)

=3

3

−

3

cot30+3−3cot30

=3

3

−

3

cot30+

3

3

−

3

3

cot30

=3

3

−

3

cot30(1+

3

)+3

=3

3

−

tan30

cot30

(1+

3

)+3

=3

3

−

tan30

cot30

tan45−

tan30tan30

cot30

+cot

2

30

=tan

3

60−2sin60

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