Question

A grinding wheel of mass 5.0kg and diameter 0.4m is rotating with an angular speed of 2 rev per sec.calculate the torque which will increase it's angular speed to 8 revolution per second in 2s

Answer 1

Answer:

Explanation:

Answer-

τ = 251.33 Nm

◆ Explanation-

# Given-

m = 5 kg

r = 4/2 = 2 m

f1 = 2 rps

f2 = 8 rps

t = 2 s

# Solution-

Rotational acceleration is-

α = (ω2-ω1) / t

α = 2π(f2-f1) / t

α = 2π(8-2) / 2

α = 4π rad/s^2

Moment of inertia is -

I = mr^2

I = 5 × 2^2

I = 20 kgm^2

Rotational torque is calculated by-

τ = Iα

τ = 20 × 4π

τ = 251.33 Nm

Therefore, torque required is 251.33 Nm.

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