Question

{(3×10^-2)^2+(4×10^-2)^2}^3/2​

Answer 1

Answer:

{(3×10^-2)^2+(4×10^-2)^2}^3/2

={(3/10^2)^2+(4/10^2)^2}^3/2

={(3/100)^2+(4/100)^2}^3/2

={9/10^4+16/10^4}^3/2

={(9+16)/10^4}^3/2

={25/10^4}^3/2

={5/10^2)^3

=125/10^6

=125×10^-6

=0.000125