Question

3×10^20 electrons flow through a cross-section of a metallic wire in 16 sec.The electric current in the wire is [given,charge of an electron=1.6×10^-19C]
(A)16A
(B)48A
(C)3A
(D)5.1A​

Answer 1

Answer:

c) 3A

Explanation:

i=q/t

q=ne

i=(3*10^20*1.6*10^-19)/16

=3*1.6*10/16

=3

i=3A

Answer 2

Answer:

❤️꧁༒☬☠PRINCE☠︎☬༒꧂❤️

Explanation:

CORRECT ANSWER ➡️ i = 3A