Question

I have two leaking taps in my kitchen. The first tap drips once every 8 seconds and
the second one drips once every 12 seconds. When any one tap drips alone, I call it
a 'SINGLE DRIP' and when both drip simultaneously, I call it a
'DOUBLE DRIP'. The number of 'SINGLE DRIPS' in an interval of 100
seconds following a 'DOUBLE DRIP' will be
a) 3
b) 7
c) 12
d) 18

Answer 1

C) 12 is the correct answer

Answer 2

Solution :-

given that,

→ The first tap drips in = every 8 seconds

→ The second tap drips in = every 12 seconds

so,

→ Both tap drips together in = LCM of (8 and 12)

checking prime factors we get,

→ 8 = 2 * 2 * 2

→ 12 = 2 * 2 * 3

then,

→ LCM = 2 * 2 * 2 * 3 = 24 seconds .

therefore,

→ Double drips in interval of 100 seconds = 100 ÷ 24 = 4 Quotient .

hence, required DOUBLE DRIP' will be 4 .

Learn more :-

वह छोटी से छोटी संख्या बताईये जिसमे 7,9,11 से भाग देने पर 1,2,3 शेष बचे

https://brainly.in/question/9090122