3/10 < log10 (2) < 1/3
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Ishitaa1:
we gotta prove that without using log table
we gotta prove that without using log table
we gotta prove that without using log table
we gotta prove that without using log table
we gotta prove that without using log table
we gotta prove that without using log table
i mean using log graph
need to prove that without using log graph
kk ela
need to prove that without using log graph
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y1 = lg2 -3/10 y2=lg2- 1/3
= 3*lg2 - lg10^3 =3*lg2 - lg10
=lg2^3 - lg1000 =lg8/10
= lg(8/1000)
z =y2 - y1
= lg(8/10) - lg(8/1000)
= lg(1000/10)
=lg100
=lg10^2
=2
accordingly y2 - y1>0
y2>y1
= 3*lg2 - lg10^3 =3*lg2 - lg10
=lg2^3 - lg1000 =lg8/10
= lg(8/1000)
z =y2 - y1
= lg(8/10) - lg(8/1000)
= lg(1000/10)
=lg100
=lg10^2
=2
accordingly y2 - y1>0
y2>y1
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