Question

3
105°
30°
B
8
Side AB is of length 8 units, then what is the
area of AABC?

Answer 1

Answer:

In a triangle ABC, a/sin A = b/sin B = c/sin C

The angles of a triangle add up to 180 degrees.

A = 30 degrees and C = 105 degrees, this gives B = 180 - 30 - 105 = 45 degrees.

a/sin A = b/sin B

=> 8/sin 30 = b/sin 45

=> b = 8*sin 45/sin 30

=> b = 8*2/sqrt 2

=> b = 8* sqrt 2

=> b = 11.31

The side b is 11.31

Answer 2

Answer:

In a triangle ABC, a/sin A = b/sin B = c/sin C

The angles of a triangle add up to 180 degrees.

A = 30 degrees and C = 105 degrees, this gives B = 180 - 30 - 105 = 45 degrees.

a/sin A = b/sin B

=> 8/sin 30 = b/sin 45

=> b = 8*sin 45/sin 30

=> b = 8*2/sqrt 2

=> b = 8* sqrt 2

=> b = 11.31

The side b is 11.31