Question

(-3/11)^x+5 ÷(-3/11)^-2x+3=(-3/11)^2x-5×(-3/11)^-2x-8

Answer 1

First Convert The Bases To Make Them The Same,

We Get,

(-3/11)^x+5-(-2x+3)=(-3/11)^2x-5+(-2x-8)

On Simplifying,

(-3/11)^3x+2=(-3/11)^(-13)

As Bases Are The Same,

Equate The Powers,

So, We Get, 3x+2 = -13

So, x = -5

You Can Put Values And Evaluate.

Thanks

Answer 2

The value of x is -5.

Step-by-step explanation:

Consider the given equation is

$(-\dfrac{3}{11})^{x+5}\div (-\dfrac{3}{11})^{-2x+3}=(-\dfrac{3}{11})^{2x-5}\times (-\dfrac{3}{11})^{-2x-8}$

Using properties of exponent we get

$(-\dfrac{3}{11})^{x+5-(-2x+3)}=(-\dfrac{3}{11})^{2x-5+(-2x-8)}$

$(-\dfrac{3}{11})^{3x+2}=(-\dfrac{3}{11})^{-13}$

On comparing both sides we get

$3x+2=-13$

$3x=-13-2$

$3x=-15$

Divide both sides by 5.

$x=-5$

Therefore, the value of x is -5.

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