3.14(a2 + ab) when a = 4 and b = 3
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3.14(4*4+4*3)
3.14(16+12)
3.14(28)
22*28/7. (3.14=22/7approximately)
22*4=88(approx)
Answered by
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Answer:
Required value of 3.14( a^2 + ab ) is 87.92
Step-by-step explanation:
It is given that the numeric value of a and b is 4 and 3 respectively.
We have to find the result of the equation 3.14( a^2 + ab ), when value of a is 4 and b is 3.
To find the result, we have to substitute the values of a and b in the given equation.
Substituting the values : -
= > 3.14{ ( 4 )^2 + ( 4 x 3 ) }
= > 3.14{ 16 + 12 }
= > 3.14{ 28 }
= > 3.14 x 28
= > 87.92
Hence the required value of 3.14( a^2 + ab ) is 87.92, when a is 4 and b is 3.
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