Question

3.14(a2 + ab) when a = 4 and b = 3

Answer 1

3.14(4*4+4*3)

3.14(16+12)

3.14(28)

22*28/7. (3.14=22/7approximately)

22*4=88(approx)

Answer 2

Answer:

Required value of 3.14( a^2 + ab ) is 87.92

Step-by-step explanation:

It is given that the numeric value of a and b is 4 and 3 respectively.

We have to find the result of the equation 3.14( a^2 + ab ), when value of a is 4 and b is 3.

To find the result, we have to substitute the values of a and b in the given equation.

Substituting the values : -

= > 3.14{ ( 4 )^2 + ( 4 x 3 ) }

= > 3.14{ 16 + 12 }

= > 3.14{ 28 }

= > 3.14 x 28

= > 87.92

Hence the required value of 3.14( a^2 + ab ) is 87.92, when a is 4 and b is 3.