3.15 gm of an acid is dissolved in water and makes the volume 500 ml. 20 ml of this
solution requires 20 ml of N/10 NaOH solution to neutralize. If acid is dibasic, calculate
its molar mass.
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Answer:
126 gm
Explanation:
initially find its molarity i.e.= 6.30/m
now N1V1=N2V2
Normality = n factor into molarity
2*6.30/m*20 = 20* 1/10
solve this and you will get m=126 gm
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