(3^2)^0+3^-4×3^6+(1/3)^-2
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Answered by
21
(3^2) ^0=3^0=1
3^(-4) ×3^6=3^(-4)+6=3^2
So, 1+3^2+3^2
1+9+9=19
3^(-4) ×3^6=3^(-4)+6=3^2
So, 1+3^2+3^2
1+9+9=19
subham19:
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Answered by
16
(3^2)^0+3^(-4)x3^6+(1/3)^(-2)
=1+(1/3^(4))x3^6+3^2
=1+3^2+3^2
=1+18
=19
=1+(1/3^(4))x3^6+3^2
=1+3^2+3^2
=1+18
=19
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