(3^2)0 +3-4×3^6+(1÷3)-2
Answers
Answered by
3
You need to consider the order of operations.
First, we evaluate what is inside the parenthesis:
15−(−3)2+(4−4)3⋅[5+(−3)⋅(−6)]=15−(−3)2+03⋅[5+(−3)⋅(−6)]
15
−
(
−
3
)
2
+
(
4
−
4
)
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
(
−
3
)
2
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
Next, we evaluate the exponents:
15−(−3)2+03⋅[5+(−3)⋅(−6)]=15−9+03⋅[5+(−3)⋅(−6)]
15
−
(
−
3
)
2
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
Next, we evaluate any multiplication and division:
15−9+03⋅[5+(−3)⋅(−6)]=15−9+0⋅[5+(−3)⋅(−6)]
15
−
9
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
15−9+0⋅[5+(−3)⋅(−6)]=15−9+0
15
−
9
+
0
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
Finally, we evaluate any addition and subtraction:
15−9+0=6
First, we evaluate what is inside the parenthesis:
15−(−3)2+(4−4)3⋅[5+(−3)⋅(−6)]=15−(−3)2+03⋅[5+(−3)⋅(−6)]
15
−
(
−
3
)
2
+
(
4
−
4
)
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
(
−
3
)
2
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
Next, we evaluate the exponents:
15−(−3)2+03⋅[5+(−3)⋅(−6)]=15−9+03⋅[5+(−3)⋅(−6)]
15
−
(
−
3
)
2
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
Next, we evaluate any multiplication and division:
15−9+03⋅[5+(−3)⋅(−6)]=15−9+0⋅[5+(−3)⋅(−6)]
15
−
9
+
0
3
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
15−9+0⋅[5+(−3)⋅(−6)]=15−9+0
15
−
9
+
0
⋅
[
5
+
(
−
3
)
⋅
(
−
6
)
]
=
15
−
9
+
0
Finally, we evaluate any addition and subtraction:
15−9+0=6
Answered by
0
-241 is the answer
(3^2)0+3-4×3^6+(1÷3)-2
0+(-1)×3^6+-2÷3
-1×3^6+-2÷3
-1×3^5-2
-1×243-2
-1×241
-241
(3^2)0+3-4×3^6+(1÷3)-2
0+(-1)×3^6+-2÷3
-1×3^6+-2÷3
-1×3^5-2
-1×243-2
-1×241
-241
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