Math, asked by riya8190, 1 year ago

(3^2)0 +3-4×3^6+(1÷3)-2

Answers

Answered by himanshusingh52
3
You need to consider the order of operations.

First, we evaluate what is inside the parenthesis:

15−(−3)2+(4−4)3⋅[5+(−3)⋅(−6)]=15−(−3)2+03⋅[5+(−3)⋅(−6)]
15

(

3
)
2
+
(
4

4
)
3

[
5
+
(

3
)

(

6
)
]
=
15

(

3
)
2
+
0
3

[
5
+
(

3
)

(

6
)
]

Next, we evaluate the exponents:

15−(−3)2+03⋅[5+(−3)⋅(−6)]=15−9+03⋅[5+(−3)⋅(−6)]
15

(

3
)
2
+
0
3

[
5
+
(

3
)

(

6
)
]
=
15

9
+
0
3

[
5
+
(

3
)

(

6
)
]

Next, we evaluate any multiplication and division:

15−9+03⋅[5+(−3)⋅(−6)]=15−9+0⋅[5+(−3)⋅(−6)]
15

9
+
0
3

[
5
+
(

3
)

(

6
)
]
=
15

9
+
0

[
5
+
(

3
)

(

6
)
]

15−9+0⋅[5+(−3)⋅(−6)]=15−9+0
15

9
+
0

[
5
+
(

3
)

(

6
)
]
=
15

9
+
0

Finally, we evaluate any addition and subtraction:

15−9+0=6
Answered by ray060504
0
-241 is the answer
(3^2)0+3-4×3^6+(1÷3)-2
0+(-1)×3^6+-2÷3
-1×3^6+-2÷3
-1×3^5-2
-1×243-2
-1×241
-241
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