Question

3×^2+10×+8=0, 3y^2+7y+4=0​

Answer 1

Step-by-step explanation:

3x2+10x+8=0

3x2+4x+6x+8=0

x(3x+2)+2(3x+8)=0

(3x+2)+(x+2)=0

x=-2/3or x=-2

3y2+7y+4=0

3y2+3y+4y+4=0

3y(y+1)+4(y+1)=0

(y+1)(3y+4)=0

y=-1,y=-4/3

Answer 2

Answer:

$y = - 1,y = \frac{ - 4}{3}$

Step-by-step explanation:

It is the correct answer.