Question

3.ײ- 16× + 64 = 0 solve this guys.​

Answer 1

refer to the above attachment for your answer

hope it's helpful :)

sorry I'm too lazy to type the answer right now :p

Answer 2

Answer:

${x}^{2} - 16x + 64 = 0 \\ {x}^{2} - 2 \times 8 \times x + {8}^{2} = 0 \\ {(x - 8)}^{2} = 0 \\ x = 8$