Question

3-2√2/3+2√2 rationalise

Answer 1

$\frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \\ \\ = \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ = \frac{( {3 - 2 \sqrt{2} })^{2} }{ {3}^{2} - ( {2 \sqrt{2}) }^{2} } \\ \\ = \frac{9 + 8 - 12 \sqrt{2} }{9 - 8} \\ \\ = 17 - 12 \sqrt{2}$