у – 3у2 + 2y – 6 – xy + 3x
Answers
Answered by
6
Answer:
Given that: y
3
−3y
2
+2y−6−xy+3x
=(y
3
−3y
2
)+(2y−6)+(−xy+3x), (group pair of terms)
=y
2
(y−3)+2(y−3)−x(y−3), (factor each binomials)
=(y−3)(y
2
+2−x) , (factor out common factor (y−3))
The common factors of y
3
−3y
2
+2y−6−xy+3x are (y−3)(y
2
+2−x)
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