show that tan3x tan2xtanx=tan3x-tan2x-tanx
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∵tan3x=tan(2x+x)⇒tan3x=1−tan2x.tanxtan2x+tanx⇒tan3x−tan3xtan2xtanx=tan2x+tanx⇒tan3x−tan2x−tanx=tan3xtan2xtanx
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