Question

(3^-2+3^-3)*(3^0-3^-1)=?​

Answer 1

Answer:

$( {3}^{2} + {3}^{3} ) \times ( {3}^{0} - {3}^{ - 1} ) \\ = (9 + 27) \times (1 - \frac{1}{3} ) \\ = 36 \times \frac{3 - 1}{3} \\ \\ = 36 \times \frac{2}{3} \\ \\ = 12 \times 2 \\ = 24$

24

Step-by-step explanation:

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