Question

3√2/√3+√6-4√3/√6+√2+√6/√2+√3

Answer 1

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Answer 2

Answer:

$\frac{3 \sqrt{2} }{ \sqrt{3} } + \frac{ \sqrt{6} - 4 \sqrt{3} }{ \sqrt{2} } + \frac{ \sqrt{6} }{ \sqrt{2} + \sqrt{3} } \\ = > \frac{3 \sqrt{6} }{3} + \frac{ \sqrt{12} - 4 \sqrt{6} }{2} + \frac{ \sqrt{12} - \sqrt{18} }{ - 1} \\ = > \frac{6 \sqrt{6} +3 \sqrt{12} - 12 \sqrt{6} - 6 \sqrt{12} + 6 \sqrt{18} }{6} \\ = > \frac{18 \sqrt{2} - 6 \sqrt{6} - 3 \sqrt{12} }{6} \\ = > \frac{6(3 \sqrt{2} - \sqrt{6} - \sqrt{3}) }{6}(since \: 3 \sqrt{12} = 3 \sqrt{3 \times 4} = 6 \sqrt{3} ) \\ = > 3 \sqrt{2} - \sqrt{6} - \sqrt{3}$