3/2 and 1 are the first two terms of gp. Find the fourth term
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Let first term =A and second term = Ar
then A=3/2 and Ar=1
substituting value of A in in 2nd 3/2×r=1
=> r=2/3
so 4th term = Ar^3 = 3/2×(2/3)^3 = 4/9
thanks
then A=3/2 and Ar=1
substituting value of A in in 2nd 3/2×r=1
=> r=2/3
so 4th term = Ar^3 = 3/2×(2/3)^3 = 4/9
thanks
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