Question

3/2 x1/5 + 7/5+3/2 using correct property ..? please help me out with the answer​

Answer 1

Answer:

Firstly,

3/2×1/5+7/5+3/2

Using. the Bodmas rule

(Bracket

Of

Division

Multiplication

Addition

subtraction)

first we multiply 3/2 and 1/5 and at the same time

add 7/5+3/2

i.e 3/10+29/10

adding it we get,

32/10.

which is the final answer of the question.

Answer 2

$\mathfrak{ \red{ \underline{Solution}:-}} \\ \\ \blue{ = > } \frac{3}{2} \times \frac{1}{5 } + \frac{7}{5} + \frac{3}{2}$

$\underline{we \: use \:{ \red{BODMAS} } \: rule \: with}$

$\red{ \underline{Property}:-} \\ \\{ \blue{ = > } } \: a \times b \ + c + d \\ \\ { \blue{ = > } } \: ab + c + d$

$\red{now}$

$\blue{ = > } \frac{3}{2} \times \frac{1}{5 } + \frac{7}{5} + \frac{3}{2} \\ \\ \blue{ = > } \: \frac{3}{10} + \frac{7}{5} + \frac{3}{2} \\ \\ \blue{ = > } \frac{3}{10} + \frac{7 \times 2}{5 \times 2} + \frac{3 \times 5}{2 \times 5} \\ \\ \blue{ = > } \frac{3}{10 } + \frac{14}{10} + \frac{15}{10} \\ \\ \blue{ = > } \frac{3 + 14 + 15}{10} \\ \\ \blue{ = > } \frac{32}{10} \\ \\ \blue{ = > } \red{3.2} \\ \\ \\ \fbox{ \underline{i \: hope \: it \: helps \: you.}}$