Physics, asked by bhoomigarg700477, 10 months ago

A body weigh 70 N in air. It displaces 0.002 m³ of water when fully immersed into water. (Take g = 10 m/s²) and density of water = 1000 kg/m³)
Calculate:
(1) Weight of the water displaced.
(ii) Weight of the object in water.

Answers

Answered by bhaisora9
1

Answer:

According to Archimedes Principle "when a body is fully or partially immersed in a fluid at rest,it appears to lose weight.In other words,

Apparent weight W

=W−F

b

where F

b

is buoyancy force which is equal to weight of displaced liquid.

Apparent weight 8N=10N−F

b

F

b

=2N

or the weight of the liquid displaced by the object 2N.

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