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28. If one root of the quadratic equation 3x2+px+4=0 is 2/3, then find the value
of p and the other root of the equation
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Answer:
p = -8 and x = 2
Step-by-step explanation:
p(x) = 3x^2 + px + 4
p(2/3) = 3(2/3)^2 + p(2/3) + 4 =0
4/3 + 2p/3 + 4 = 0
p = -8
3x^2 + px + 4 = 0
3x^2 - 8x + 4 = 0
3x^2 - 6x - 2x + 4 = 0
(3x - 2) (x-2) = 0
X=2/3 or x=2
Hence, x = 2
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