Question

(3+2i)^2/(4−3i), Find the modulus

Answer 1

Answer : 13/5

Solution :

As we know that :

(a + b)² = a² + 2ab + b²

Such as :

(3 + 2i)² = 9 + 12i + 4i²

( As we know that : i² = -1 )

(3 + 2i)² = 9 + 12i - 4 = 5 + 12i

Now, To find :

(3 + 2i)²/(4 - 3i) = (5 + 12i)/(4 - 3i)

Modulus :

√5²+12²/√4²+(-3)²

=> √25+144/√16+9

=> √169/√25 = 13/5

I hope it will be helpful for you ☺️

Fóllòw MË ❤️