3√2x^2-5x-√2=0 find the root of the following equation by factorisation method
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Hi ,
3√2x² -5x - √2 = 0
3√2x² - 3x - 2x - √2 = 0
3x ( √2x - 1 ) - √2 ( √2x - 1 ) = 0
( √2x - 1 ) ( 3x - √2 ) = 0
Therefore ,
( √2x - 1 ) = 0 or 3x - √2 = 0
√2x = 1 or 3x = √2
x = 1/√2 or x = √2/3
I hope this helps you.
:)
3√2x² -5x - √2 = 0
3√2x² - 3x - 2x - √2 = 0
3x ( √2x - 1 ) - √2 ( √2x - 1 ) = 0
( √2x - 1 ) ( 3x - √2 ) = 0
Therefore ,
( √2x - 1 ) = 0 or 3x - √2 = 0
√2x = 1 or 3x = √2
x = 1/√2 or x = √2/3
I hope this helps you.
:)
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