Question

3+2x/2x+3=5/x+4 solve​

Answer 1

Cancel terms that are in both the numerator and denominator

$\sf3 + \frac{2x}{2} .x + 3 = \frac{5}{x} + 4 \\ \\ \sf3 + xx + 3 = \frac{5}{x} + 4$

Combine exponents

$\sf3 + xx + 3 = \frac{5}{x} + 4 \\ \\ \sf3 + {x}^{2} + 3 = \frac{5}{x} + 4$

Add the numbers

$\sf3 + {x}^{2} + 3 = \frac{5}{x} + 4 \\ \\ \sf6 + {x}^{2} = \frac{5}{x} + 4$

Rearrange terms

$\sf6 + {x}^{2} = \frac{5}{x} + 4 \\ \\ \sf {x}^{2} + 6 = \frac{5}{x} + 4$

Multiply all terms by the same value to eliminate fraction denominators

$\sf {x}^{2} + 6 = \frac{5}{x} + 4 \\ \\ \sf \: x( {x}^{2} + 6) = x( \frac{5}{x} + 4)$

Let's Simplify:-

$\sf {x}^{3} + 6x = 4x + 5 \: \red{answer}$